Q. Reactance of a capacitor of capacitance $C\mu F$ for ac frequency $\frac{400}{\pi}Hz$ is $25\Omega$. The value $C$ is
A) $50\mu F$
B) $25\mu F$
C) $100\mu F$
D) $75\mu F$
Explanation
(a) $X_{C} = \frac{1}{2\pi vC} \Rightarrow C = \frac{1}{2\pi vX_{C}} = \frac{1}{2 \times \pi \times \frac{400}{\pi} \times 25} = 50\ \mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.