Q. Two coils have mutual inductance 0.005 H. The current changes in the first coil according to equation $i = i_{0}\sin{\omega t\ where\ i_{0} = 10\ }$A and $\omega = 100\pi\ rads^{- 1}.$ The maximum value of emf in second coil is
A) 2 $\pi$
B) 5 $\pi$
C) $\pi$
D) 4 $\pi$
Explanation
(b) As $e = M\frac{di}{dt} = M\frac{d}{dt}(i_{0}\ \sin\ \omega t)$
$\therefore$ $e = Mi_{0}\cos{\omega t(\omega)}$
$e_{\max} = \ Mi_{0} \times 1 \times \omega\ $
= 0.005 $\times 10 \times 10\pi = 5\pi$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.