Q. A resistor and a capacitor are connected in series with an AC source. If the potential drop across the capacitor is 5 V and that across resistor is 12 V, then applied voltage is
A) 13 V
B) 17 V
C) 5 V
D) 12 V
Explanation
(a) Let the applied voltage be $V$ volt.
Here, $V_{R} = 12\ V,\ V_{C} = 5\ V$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ V = \sqrt{V_{R}^{2} + V_{C}^{2}} = \ \sqrt{(12)^{2} + (5)^{2}}$
$= \sqrt{144 + 25} = \sqrt{169} = 13$V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.