Q. The phase difference between the voltage and the current in an ac circuit is $\pi/4$. If the frequency is $50\ Hz$ then this phase difference will be equivalent to a time of
A) 0.02 $s$
B) 0.25 $s$
C) 2.5 $ms$
D) 25 $ms$
Explanation
(c) Time difference $= \frac{T}{2\pi} \times \phi = \frac{(1/50)}{2\pi} \times \frac{\pi}{4} = \frac{1}{400}s = 2.5m$-$s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.