Q. In L – R circuit, resistance is $8\ \Omega$ and inductive reactance is $6\ \Omega$ , then impedance is
A) $2\ \Omega$
B) $14\ \Omega$
C) $4\ \Omega$
D) $10\ \Omega$
Explanation
(d) In series L – R circuit, impedance is given by
$\ \ \ Z = \sqrt{R^{2} + X_{L}^{2}}$
Where R is the resistance and $X_{L}$ the inductive reactance.
Given, $R = 8\Omega,\ X_{L} = 6\Omega$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Z = \sqrt{(8)^{2} + (6)^{2}}$
$= \sqrt{64 + 36}$
$= \sqrt{100} = 10\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.