Q. In an ideal transformer, the voltage is stepped down from 11 kV to 220 V. If the primary current be 100 A, the current in the secondary should be
A) 5 kA
B) 1 kA
C) 0.5 kA
D) 0.1 kA
Explanation
(c) $e = \frac{E_{P}i_{P}}{E_{s}} = \frac{1100 \times 100}{220} = 500$ A=0.5 kA
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.