In the circuit shown in figure, a conducting wire $HE$ is moved with a constant speed $v$ towards legt. Th complete circuit is placed in a uniform magnetic field $\overrightarrow{B}$ perpendicular to the plane of circuit inwards. The current in $HKDE$ is [image:7_image15.png]

Question

Dr. Abubacker · Accepted Answer

(d) Potential difference across the capacitor = emf induced across $HE = Blv$ which is constant. Therefore, charge stored in the capacitor is constant. Hence current in the circuit $HKDE$ is zero.

Q. In the circuit shown in figure, a conducting wire $HE$ is moved with a constant speed $v$ towards legt. Th complete circuit is placed in a uniform magnetic field $\overrightarrow{B}$ perpendicular to the plane of circuit inwards. The current in $HKDE$ is

Explanation

Reviewed by Dr. Abubacker

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