Q. If $E_{0}$ is the peak emf, $I_{0}$ is the peak current and $\phi$ is the phase difference between them, then the average power dissipation in the circuit is
A) $\frac{1}{2}E_{0}I_{0}$
B) $\frac{E_{0}I_{0}}{\sqrt{2}}$
C) $\frac{1}{2}E_{0}I_{0}\sin\phi$
D) $\frac{1}{2}E_{0}I_{0}\cos\phi$
Explanation
(d) The average power dissipation in the circuit is $\frac{1}{2}E_{0}I_{0}\tan\phi$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.