Q. The output current versus time curve of a rectifier is shown in the figure. The average value of output current in this case is

A) 0
B) $\frac{I_{0}}{2}$
C) $\frac{2I_{0}}{\pi}$
D) $I_{0}$
Explanation

(c) $I_{av} = \frac{\int_{0}^{T/2}{i\ dt}}{\int_{0}^{T/2}{dt}} = \frac{\int_{0}^{T/2}{I_{0}\sin{(\omega t)dt}}}{T/2}$
$= \frac{2I_{0}}{T}\left\lbrack \frac{- \cos{\omega t}}{\omega} \right\rbrack_{0}^{T/2} = \frac{2I_{0}}{T}\left\lbrack - \frac{\cos\left( \frac{\omega T}{2} \right)}{\omega} + \frac{\cos{0{^\circ}}}{\omega} \right\rbrack$
$= \frac{2I_{0}}{\omega T}\left\lbrack - \cos\pi + \cos{0{^\circ}} \right\rbrack = \frac{2I_{0}}{2\pi}\lbrack 1 + 1\rbrack = \frac{2I_{0}}{\pi}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.