Q. An ac source is rated at $220V,\ 50\ Hz$. The time taken for voltage to change from its peak value to zero is
A) 50 $\sec$
B) 0.02 $\sec$
C) 5 $\sec$
D) $5 \times 10^{- 3}\ sec$
Explanation
(d) Required time $t = T/4 = \frac{1}{4 \times 50} = 5 \times 10^{- 3}\sec$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.