(b) $\cos\phi = \frac{R}{Z} = \frac{R}{\sqrt{R^{2} + \omega^{2}L^{2}}}$ $= \frac{12}{\sqrt{(12)^{2} + 4 \times \pi^{2} \times (60)^{2} \times (0.1)^{2}}} \Rightarrow \cos\phi = 0.30$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.