Q. The current flowing in a step down transformer 220 V to 22 V having impedance 220 $\Omega$ is
A) 1 A
B) 0.1 A
C) 2 mA
D) 0.1 mA
Explanation
(b) $i_{s} = \frac{E_{s}}{Z} = \frac{22}{220} = 0.1$ A
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.