Q. An AC voltage source has an output of $\Delta V = (200V)\sin{2\pi ft.}$ This source is connected to a $100\ \Omega$ resistor. RMS current in the resistance is
A) 1.41 A
B) 2.41 A
C) 3.41 A
D) 0.71 A
Explanation
(a) $I_{0} = \frac{V_{0}}{R} = \frac{200}{100} = 2\ A$
$I_{rms} = \frac{I_{0}}{\sqrt{2}} = 1.414\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.