Q.
Current growth in two $L - R$ circuits (ii) and (iii) is as shown in figure (i). Let $L_{1},\ L_{2},\ R_{1}\ and\ R_{2}$ be the corresponding values in two circuits. Then
A) $L_{1} > L_{2}$
B) $L_{1} < L_{2}$
C) $R_{1} > R_{2}$
D) $R_{1} = R_{2}$
Explanation
(b) As is for Fig. (i), steady state current for t = both the circuits is same. Therefore,
$\ \ \ \ \frac{V}{R_{1}} = \frac{V}{R_{2}}\ $
Or $R_{1}\ = R_{2}$
Again, from the same figure, we observe that
$\tau_{1} < \tau_{2}\ \ \ \ \therefore\frac{L_{1}}{R_{1}} < \frac{L_{2}}{R_{2}}\ $
As $R_{1} = R_{2},\ \ therefore,\ L_{1} < L_{2}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.