Explanation

(b) We know that Q - factor of series resonant circuit is given as
$Q = \frac{\omega_{r}L}{R}$
Here, $L = 8.1\ mH,\ C = 12.5\ \mu F,\ R = 10\Omega,\ f = 500\ Hz$
$\therefore\ \ \ \ \ \ \ \ Q = \frac{\omega_{r}L}{R} = \frac{2\pi fL}{R}$
$= \frac{2 \times \pi \times 500 \times 8.1 \times 10^{- 3}}{10} = \frac{8.1\pi}{10} = 2.5434$