Q.
The $r.m.s.$ value of potential difference $V$ shown in the figure is
A) $V_{0}/2$
B) $V_{0}/\sqrt{3}$
C) $V_{0}$
D) $V_{0}/\sqrt{2}$
Explanation
(d) $V_{rms} = \sqrt{\frac{(T/2)V_{0}^{2} + 0}{T}} = \frac{V_{0}}{\sqrt{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.