Q. The time taken by AC of 50 Hz in reaching from zero to the maximum value is
A) $50 \times 10^{- 3}\ s$
B) $5 \times 10^{- 3}\ s$
C) $1 \times 10^{- 3}\ s$
D) $2 \times 10^{- 3}\ s$
Explanation
(b) The time taken by AC in reaching from zero to maximum value is
$t = \frac{T}{4} = \frac{1}{4\ f}$
$\ \ \ \ \ \ = \frac{1}{50 \times 4} = 5 \times 10^{- 3}s\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.