Q. Two circuits have mutual inductance of 0.09 H. Average emf induced in the secondary by a change of current from 0 to 20 A in 0.006 s in primary will be
A) 120 V
B) 200 V
C) 180 V
D) 300 V
Explanation
(d) $e = \frac{MdI}{dt} = 0.09\ \times \frac{20}{0.006} = 300$V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.