Q. The instantaneous values of current and emf in an ac circuit are $I = 1/\sqrt{2}\ $ $\sin{314\ t\ amp}$ and $E = \sqrt{2}\sin{(314\ t - \pi/6)}V$ respectively. The phase difference between $E$ and $I$ will be
A) $- \pi/6\ rad$
B) $- \pi/3\ rad$
C) $\pi/6\ rad$
D) $\pi/3\ rad$
Explanation
(a) Phase difference relative to the current
$\phi = \left( 314t - \frac{\pi}{6} \right) - (314\ t) = - \frac{\pi}{6}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.