Q.
The current i passed in any instrument in an AC circuit is $i\ = 2\sin{\omega t\ A}$ and potential difference applied is given by $V = 5\cos{\omega t}\ V$. Power loss in the instrument is
A) 10 W
B) 5 W
C) Zero W
D) 20 W
Explanation
The correct answer is Option A: 10 W.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.