Q. An alternating voltage is connected in series with a resistance $R$ and an inductance $L$. If the potential drop across the resistance is $200\ V$ and across the inductance is $150\ V$, then the applied voltage is
A) 350 $V$
B) 250 $V$
C) 500 $V$
D) 300 $V$
Explanation
(b) The applied voltage is given by $V = \sqrt{V_{R}^{2} + V_{L}^{2}}$
$V = \sqrt{(200)^{2} + (150)^{2}} = 250\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.