Q. In an AC circuit the voltage applied is $E = E_{0}\sin{\omega t.}$ The resulting current in the circuit is $I = I_{0}\sin\left( \omega t - \frac{\pi}{2} \right)$. The power consumption in the circuit is given by
A) $P = \frac{E_{0}I_{0}}{\sqrt{2}}$
B) P = zero
C) $P = \frac{E_{0}I_{0}}{2}$
D) $P = \sqrt{2}E_{0}I_{0}$
Explanation
(b) For given circuit current is lagging the voltage by $\pi/2,$ so circuit is purely inductive and there is no power consumption in the circuit. The work done by battery is stored as magnetic energy in the inductor.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.