Q. A $220\ V$, 50 $Hz$ ac source is connected to an inductance of $0.2\ H$ and a resistance of $20\ ohm$ in series. What is the current in the circuit
A) 10 $A$
B) 5 $A$
C) 33.3 $A$
D) 3.33 $A$
Explanation
(d) $i = \frac{220}{\sqrt{(20)^{2} + (2 \times \pi \times 50 \times 0.2)^{2}}} = \frac{220}{66} = 3.33\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.