Q. The peak value of an alternating current is 5 A and its frequency is 60 Hz. Find its rms value and time taken to reach the peak value of current starting from zero.
A) 3.536A; 4.167 ms
B) 3.536 A;15 ms
C) 6.07 A; 10 ms
D) 2.536 A; 4.167 ms
Explanation
(a) $i_{rms} = \frac{i_{0}}{\sqrt{2}} = \frac{5}{\sqrt{2}} = 3.536\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.