(b) Here, $i = i_{0}\ at\ t = \infty.Let\ i$ be the current at $t$ = 1 s
From $i = i_{0}\left( 1 - e^{- \frac{R}{L}t} \right)$
= $i_{0}\left( 1 - e^{- \frac{10}{5} \times 1} \right) = i_{0}\left( 1 - \frac{1}{e^{2}} \right)$
$\therefore\ \ \frac{i_{0}}{i} = \ \frac{e^{2}}{e^{2} - 1\ }$