Q. In an induction coil, the coefficient of mutual inductance is 4H. If current of 5A in the primary coil is cut off $i$ 1/ 1500s, the emf at the terminals of the secondary coil will be
A) 15 kV
B) 60 kV
C) 10 kV
D) 30 kV
Explanation
(d) $e = Ldi/dt$ = 4 $\times \frac{5}{1/1500} = 30000$V=30kV
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.