Q. A capacitor $50\mu F$ is connected to a supply of 220 V and angular frequency $50\ $rad$\ s^{- 1}$. The value of rms current in the circuit is

A) 0.45 A
B) 0.50 A
C) 0.55 A
D) 0.60 A
Explanation

(c) Reactance of capacitor or capacitive reactance is denoted by $X_{C},$ given by
$X_{C} = \frac{1}{\omega C}$
Given, $\omega = 50\ $rad$\ s^{- 1},\ C = 50\mu F = 50 \times 10^{- 6}F$
$\therefore\ \ \ \ \ \ \ \ \ \ \ X_{C} = \frac{1}{50 \times 50 \times 10^{- 6}}$
From Ohm’s law, current flowing through the circuit is given by
$I_{rms} = \frac{V_{rms}}{X_{C}}$
$\ \ \ \ \ \ \ \ \ = \frac{V_{rms}}{1/\omega C} = \frac{220}{1/50 \times 50 \times 10^{- 6}}\ \ \ \ \ \ \ \ \ $
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ I_{rms} = 220 \times 50 \times 50 \times 10^{- 6}$
$= 55 \times 10^{- 2}\ $A$= 0.55\ $A

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.