Q. A $12\ ohm$ resistor and a 0.21 henry inductor are connected in series to an ac source operating at $20\ volts$, 50 cycle/second. The phase angle between the current and the source voltage is
A) $30{^\circ}$
B) $40{^\circ}$
C) $80{^\circ}$
D) $90{^\circ}$
Explanation
(c) $\tan\phi = \frac{\omega L}{R} = \frac{2\pi \times 50 \times 0.21}{12} = 5.5 \Rightarrow \phi = 80{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.