Q. In a series resonant circuit, the AC voltage across resistance R, inductor L and capacitor C are 5 V, 10 V and 10 V respectively. The AC voltage applied to the current will be
A) 10 V
B) 25 V
C) 5 V
D) 20 V
Explanation
(c) Given, $V_{R} = 5\ V,\ V_{L} = 10\ V\ $and$\ V_{C} = 10\ V$
In the L – C – R circuit, the AC voltage applied to the circuit will be
$V = \sqrt{V_{R}^{2} + \left( V_{L} - V_{C} \right)^{2}}$
$= \sqrt{(5)^{2} + (10 - 10)^{2}} = 5V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.