Q. In the adjoining figure the impedance of the circuit will be
A) 120 $ohm$
B) 50 $ohm$
C) 60 $ohm$
D) 90 $ohm$
Explanation
(c) $i_{L} = \frac{90}{30} = 3A$
$i_{C} = \frac{90}{20} = 4.5\ A$
Net current through circuit $i = i_{C} - i_{L} = 1.5\ A$
$\therefore Z = \frac{V}{i} = \frac{90}{1.5} = 60\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.