Q. In an ac circuit, the $r.m.s.$ value of current, $I_{rms}$ is related to the peak current, $I_{0}$ by the relation
A) $I_{rms} = \frac{1}{\pi}I_{0}$
B) $I_{rms} = \frac{1}{\sqrt{2}}I_{0}$
C) $I_{rms} = \sqrt{2}I_{0}$
D) $I_{rms} = \pi I_{0}$
Explanation
The correct answer is Option B: $I_{rms} = \frac{1}{\sqrt{2}}I_{0}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.