Q. The values of L, C and R for a circuit are 1H, 9F and $3\Omega$. What is the quality factor for the circuit at resonance?
A) 1
B) 9
C) $\frac{1}{9}$
D) $\frac{1}{3}$
Explanation
(c) $Q = \frac{\omega L}{R} = \frac{1}{R} \times \frac{1}{\sqrt{LC}} \times L$
$= \frac{1}{R}\sqrt{\frac{L}{C}}$
$= \frac{1}{3} \times \sqrt{\frac{1}{9}} = \frac{1}{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.