Q.
In the circuit shown in figure neglecting source resistance, the voltmeter and ammeter readings will be respectively
A) 0 V, 3 A
B) 150 V, 3 A
C) 150 V, 6 A
D) 0 V, 8 A
Explanation
(d) The voltage $V_{L}$ and $V_{C}$ are equal and opposite so, voltmeter reading will be zero.
Also, $R = 30\ \Omega,\ X_{L} = X_{C} = 25\ \Omega$
So, $i = \frac{V}{\sqrt{R^{2} + \left( X_{L} - X_{C} \right)^{2}}}$
$= \frac{V}{R} = \frac{240}{30} = 8A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.