(d) $V = \sqrt{V_{R}^{2} + \left( V_{L} - V_{C} \right)^{2}}$ $\because V_{R} = V\ \because V_{L} = V_{C}$ $\therefore\ $ Reading of voltmeter $= 220V$ Reading of ammeter $I_{rms} = \frac{E_{rms}}{Z}$ $= \frac{220}{100} = 2.2A$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.