(c) Here, $R = 10\ \Omega.$ As is known, $|dq| = \frac{d\phi}{R} = |i\ dt| = area\ under\ i - t$ graphs. $\therefore\ \ \frac{d\phi}{R} = \ \frac{(4)(0.1)}{2} = 0.2\ $ $d\phi = 0.2\ R = 0.2\ \times 10 = 2\ \ $Wb
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