(c) For an R – C circuit
Applied voltage, $V = \sqrt{{V_{R}^{2} + V}_{C}^{2}}$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 50 = \sqrt{(40)^{2} + V_{C}^{2}}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ V_{C} = 30\ V$