Q. In an AC circuit, V and I are given by $V = 150\sin{(150t)\ volt\ and\ I = 150\sin\left( 150t + \frac{\pi}{3} \right)}amp.$ The power dissipated in the circuit is
A) Zero
B) 5625 W
C) 150 W
D) 106 W
Explanation
(b) $Power\ P = \frac{1}{2}\ V_{0}I_{0}\cos\phi$
$= 0.5 \times 150 \times 150 \times \cos{60{^\circ} = \frac{22500}{4}}$
$= 5625\ W$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.