Explanation

(c) Here, $L = 25\ mH = 25 \times 10^{- 3}\ H$
$v = 50\ Hz,\ V_{rms} = 220\ V$
The inductive reactance is
$X_{L} = 2\pi v\ L = 2 \times \frac{22}{7} \times 50 \times 25 \times 10^{- 3}\ \Omega$
The $rms$ current in the circuit is
$I_{rms} = \frac{V_{rms}}{X_{L}} = \frac{220}{2 \times \frac{22}{7} \times 50 \times 25 \times 10^{- 3}}$
$= \frac{7 \times 1000}{2 \times 5 \times 25}A = 28\ A$