Q. The resonance frequency of the tank circuit of an oscillator when $L = \frac{10}{\pi^{2}}$ mH and $C = 0.04\ \mu F$ are connected in parallel is
A) 250 kHz
B) 25 kHz
C) 2.5 kHz
D) 25 MHz
Explanation
(b) In parallel resonant circuit, resonance frequency
$f_{0} = \frac{1}{2\pi\sqrt{LC}}$
$= \frac{1}{2\pi\sqrt{\frac{10 \times 10^{- 3}}{\pi^{2}} \times 0.04 \times 10^{- 6}}}$
$= \frac{10^{4}}{2 \times 0.2} = 25\ kHz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.