Q. Power delivered by the source of the circuit becomes maximum, when
A) $\omega L = \omega C$
B) $\omega L = \frac{1}{\omega C}$
C) $\omega L = - \left( \frac{1}{\omega C} \right)^{2}$
D) $\omega L = \sqrt{\omega C}$
Explanation
The correct answer is Option B: $\omega L = \frac{1}{\omega C}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.