Q. For a coil having L = 2 mH, current flows at the rate of $10^{3}\ As^{- 1}.$ The emf induced is
A) 2 V
B) 1 V
C) 4 V
D) 3 V
Explanation
(a) $e = L\frac{dI}{dt} = 2 \times 10^{- 3} = 2$V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.