Q. In a L-C-R series circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that across the resistance is 40 V. Then, supply voltage will be equal to
A) 50 V
B) 70 V
C) 130 V
D) 10 V
Explanation
(a) In L-C-R series circuit,
$V = \sqrt{V_{R}^{2} + \left( V_{L} - V_{C} \right)^{2}}$
$= \sqrt{(40)^{2} + (60 - 30)^{2}}$
$= \sqrt{1600 + 900} = \sqrt{2500} = 50$V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.