Q. A circuit has a resistance of $11\Omega$, an inductive reactance of $25\Omega$ and a capacitative resistance of $18\Omega$. It is connected to an ac source of $260V$ and $50Hz$. The current through the circuit (in amperes) is

A) 11
B) 15
C) 18
D) 20
Explanation

(d) $Z = \sqrt{R^{2} + \left( X_{L} - X_{C} \right)^{2}} = \sqrt{(11)^{2} + (25 - 18)^{2}} = 13\ \Omega$
Current $i = \frac{260}{13} = 20\ A$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.