(c) In L – R circuit, impedance $Z = \sqrt{R^{2} + X_{L}^{2}}$ Here, $X_{L} = \omega L = 2\pi\ fL$ $\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Z = \sqrt{R^{2} + 4\pi^{2}\ f^{2}L^{2}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.