Q. In L – C – R circuit, an alternating emf of angular frequency$\omega$ is applied then the total impedance will be
A) $\left\lbrack (R\omega)^{2} + \left( L\omega - \frac{1}{C\omega} \right)^{2} \right\rbrack^{1/2\ }$
B) $\left\lbrack R^{2} + \left( L\omega - \frac{1}{C\omega} \right)^{2} \right\rbrack^{\begin{array}{r}
- \frac{1}{2} \\
\
\end{array}}$
C) $\left\lbrack R^{2} + (L\omega - C\omega)^{2} \right\rbrack^{1/2\ }$
D) $\left\lbrack R^{2} + \left( L\omega - \frac{1}{C\omega} \right)^{2} \right\rbrack^{\begin{array}{r}
1/2\ \\
\
\end{array}}$
Explanation
The correct answer is Option D: $\left\lbrack R^{2} + \left( L\omega - \frac{1}{C\omega} \right)^{2} \right\rbrack^{\begin{array}{r} 1/2\ \\ \ \end{array}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.