Q. In the L-C-R circuit shown, the impedance is

A) $500\ \Omega$
B) $300\ \Omega$
C) $100\ \Omega$
D) $200\ \Omega$
Explanation

(a) $X_{L} = 2\pi fL = 2\pi\left( \frac{50}{\pi} \right) \times 1 = 100\Omega$
$X_{C} = \frac{1}{2\pi fC}$
$\ \ \ \ \ \ = \frac{1}{2\pi\left( \frac{50}{\pi} \right) \times 20 \times 10^{- 6}}$
$\ \ \ \ \ \ = 500\ \Omega$
Impedence Z = $\sqrt{(R)^{2} + \left( X_{c} - X_{L} \right)^{2}}$
$= \sqrt{(300)^{2} + (400)^{2}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 500\ \Omega$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.