Q. A transformer is having 2100 turns in primary and 4200 turns in secondary. An AC source of 120 V, 10 A is connected to its primary. The secondary voltage and current are
A) 240 V,5 A
B) 120 V, 10 A
C) 240 V, 10 A
D) 120 V, 20 A
Explanation
(a) $E_{s} = \frac{n_{s}}{n_{P}}\ E_{P} = \frac{4200}{2100} \times 120 = 240$V
$i_{s}\ = \frac{n_{s}}{n_{P}}\ i_{P} = \frac{2100}{4200} \times 10 = 5$ A
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.