Q. An electromagnetic wave, going through vacuum is described by $E = E_{0}\sin{(kx - \omega t)}$ Which of the following is independent of wavelength?
A) $k$
B) $\omega$
C) $k/\omega$
D) $k\omega$
Explanation
(c) Here, $kx = \theta\ \ or\ \ k = \theta/x$
And $\omega t = \theta_{0}\ \ \ or\ \ \ \omega = \theta_{0}/t$
$\therefore\ k/\omega = t/x = 1/(x/t) = \frac{1}{v}$, where $v$ is the velocity of electromagnetic wave, which is independent of wavelength of wave but depends upon the nature of medium of propagation of wave
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.