Q. In a plane electromagnetic wave propagating in space has an electric field of amplitude $9 \times 10^{3}\ Vm^{- 1}$, then the amplitude of the magnetic field is
A) $2.7 \times 10^{12}\ T$
B) $9.0 \times 10^{- 3}\ T$
C) $3.0 \times 10^{- 4}\ T$
D) $3.0 \times 10^{- 5}\ T$
Explanation
(d) $B_{0} = \frac{E_{0}}{c} = \frac{9 \times 10^{3}}{3 \times 10^{8}} = 3 \times 10^{- 5}\ T$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.