Q. A large parallel plate capacitor, whose plates have an area of $1\ m^{2}$ and are separated from each other by 1 mm, is being charged at a rate of $25\ Vs^{- 1}$. If the dielectric between the plates has the dielectric constant 10, then the displacement current at this instant is
A) $25\ \mu A$
B) $11\ \mu A$
C) $2.2\ \mu A$
D) $1.1\ \mu A$
Explanation
(c) $C = \frac{\varepsilon_{0}KA}{d} = \frac{(8.85 \times 10^{- 12}) \times 10 \times 1}{10^{- 3}}$
$= 8.85 \times 10^{- 8}\ F$
$i = \frac{d}{dt}(CV) = C\frac{dV}{dt} = 8.85 \times 10^{- 8} \times 25$
$= 2.2 \times 10^{- 6}$ A
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.